Hadamard matrices can be constructed using finite
field GF(
)
when
and
is odd. Pick a representation
relatively prime to
. Then by coloring white
(where
is the floor function)
distinct equally spaced residues mod
(
,
,
, ...;
,
,
, ...; etc.) in addition to 0, a Hadamard
matrix is obtained if the powers of
(mod
) run through
. For example,
(1)
|
is of this form with and
. Since
, we are dealing with GF(11), so pick
and compute its residues (mod
11), which are
(2)
| |||
(3)
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(4)
| |||
(5)
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(6)
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(7)
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(8)
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(9)
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(10)
| |||
(11)
| |||
(12)
|
Picking the first residues and adding 0 gives: 0, 1, 2, 4, 5, 8, which should
then be colored in the matrix obtained by writing out
the residues increasing to the left and up along the
border (0 through
,
followed by
),
then adding horizontal and vertical coordinates to get the residue to place in each
square.
(13)
|
To construct ,
consider the representations
. Only the first form can be used,
with
and
.
We therefore use GF(19), and color 9 residues plus 0
white.
Now consider a more complicated case. For , the only form having
is the first, so use the GF(
) field. Take as the modulus the irreducible
polynomial
,
written 1021. A four-digit number can always be written using only three digits,
since
and
.
Now look at the moduli starting with 10, where each digit is considered separately.
Then
(14)
|
Taking the alternate terms gives white squares as 000, 001, 020, 021, 022, 100, 102, 110, 111, 120, 121, 202, 211, and 221.