The knight graph is a graph
on
vertices
in which each vertex represents a square
in an
chessboard, and each edge
corresponds to a legal move by a knight (which may only make moves which simultaneously
shift one square along one axis and two along the other).
It is therefore a
-leaper graph, as well as a distance-
Euclidean distance
graph.
knight graphs abstracted from
the chessboard are illustrated above for
, ..., 6. The
knight graph is the singleton
graph
and the
knight graph is isomorphic to the empty graph
(since no square
is reachable from any other by a knight).
The knight graph consists of an 8-cycle
together with an (unreachable from all of the other squares)
isolated central vertex.
The number of edges in the knight graph is
(8 times the triangular
numbers), so for
,
2, ..., the first few values are 0, 0, 8, 24, 48, 80, 120, ... (OEIS A033996).
Knight graphs are bipartite and therefore are perfect.
The following table summarizes some named graph complements of knight graphs.
The knight graph is implemented in
the Wolfram Language as KnightTourGraph[m,
n], and precomputed properties are available using GraphData[
"Knight",
m, n
].
Closed formulas for the numbers of
-graph cycles of the
knight graph are given by
for
odd and
|
(1)
|
(E. Weisstein, Nov. 16, 2014).
A knight's path is a sequence of moves by a knight such that each square of the board is visited exactly
once. It is therefore a Hamiltonian path on the
corresponding knight graph. Conrad et al. (1994) show that a knight's path
exists on an
board iff
.
The above figures show six knight's paths on an chessboard,
all but the first of which are re-entrant. The final path
has the additional property that it is a semimagic
square with row and column sums of 260 and main diagonal sums of 348 and 168
(Steinhaus 1999, p. 30).
If the final position of such a path is a knight's move away from the initial position of the knight, the path
is called re-entrant or closed and corresponds to a Hamiltonian
cycle on the underlying knight graph. Conrad et al. (1994) shows that
a knight's tour exists on an board iff
and
is even.
Backtracking algorithms (in which the knight is allowed to move as far as possible until it comes to a blind
alley, at which point it backs up some number of steps and then tries a different
path) can be used to find knight's tours, but such
methods can be very slow. Warnsdorff (1823) proposed an algorithm
that finds a path without any backtracking
by computing ratings for "successor" steps at each position (Knuth 2025).
Here, successors of a position are those squares that
have not yet been visited and can be reached by a single move from the given position.
The rating is highest for the successor whose number of successors is least. In this
way, squares tending to be isolated are visited first
and therefore prevented from being isolated (Roth). The time needed for this algorithm
grows roughly linearly with the number of squares of the
chessboard, but unfortunately computer implementations
show that this algorithm runs into blind alleys for
chessboards bigger than , despite the fact that it works well on smaller boards
(Roth).
Conrad et al. (1994) discovered another linear time algorithm and proved that it solves the Hamiltonian path
problem for all .
The Conrad et al. algorithm works by decomposition
of the chessboard into smaller chessboards
(not necessarily square) for which explicit solutions
are known. This algorithm is rather complicated because
it has to deal with many special cases, but has been implemented in the Wolfram
Language by A. Roth. Example tours are illustrated above for
boards with
to 8.
The numbers of (undirected) closed knight's tours (i.e., Hamiltonian cycles) on a chessboard for
, 2, ... are 0, 0, 9862, 13267364410532, ... (OEIS A001230;
Ball and Coxeter 1987; Wegener 2000, p. 369; Elkies and Stanley 2003). There
are no closed tours for
boards with
odd. Kraitchik (1942, pp. 264-265) also notes that there are 1728 total paths
on the
square, 8 of which are symmetric, and there are five doubly
symmetric paths on the
square. The number of cycles
covering the directed knight's graph for an
chessboard was computed
by Wegener and Löbbing (1996) as
. They also computed the number of undirected
tours, obtaining an incorrect answer
, which is not divisible
by 4 as it must be (cf. Knuth 2025, p. 40). The correct value of
appears in Wegener's subsequent book (Wegener
2000), and also agrees with unpublished calculations by B. D. McKay (1997;
Knuth 2025, pp. 18 and 40).
The longest "uncrossed" knight's tours on an board for
, 4, ... are 2, 5, 10, 17, 24, 35, ... (OEIS A003192).
The following table extends and corrects some additional results given by Kraitchik (1942, pp. 264-265). Here, DHP means geometrically distinct Hamiltonian paths, DSHP means geometrically distinct symmetric paths, HP means total (directed) Hamiltonian paths, DHC means geometrically distinct Hamiltonian cycles, and HC means total (directed) Hamiltonian cycles.
| size | DHP | DSHP | HP | DHC | HC |
| Sloane | A118067 | A158074 | |||
| 0 | 0 | 0 | 0 | 0 | |
| 0 | 0 | 0 | 0 | 0 | |
| 3 | 16 | 0 | 0 | ||
| 0 | 0 | 0 | 0 | ||
| 0 | 0 | 0 | 0 | ||
| 14 | 2 | 104 | 0 | 0 | |
| 104 | 792 | 0 | 0 | ||
| 146 | 16 | 1120 | 0 | 0 | |
| 773 | 6096 | 8 | 32 | ||
| 2698 | 58 | 21344 | 0 | 0 | |
| 14350 | 114496 | 28 | 352 | ||
| 32296 | 257728 | 0 | 0 | ||
| 3072 | |||||
| 0 | 0 | ||||
| 30848 |
Amazingly, the number of Hamiltonian cycles on the
knight graph is given by the 21st-order linear recurrence
equation
|
(2)
|
with corresponding closed-form generating function
|
(3)
| |||
|
(4)
|
where
|
(5)
| |||||
|
(6)
|
This result was obtained independently by D. E. Knuth and N. D. Elkies in April 1994, both using the so-called transfer-matrix method (Stanley 1999, Ch. 4.7; Elkies and Stanley 2003).
The numbers of possible (directed) closed tours on a board for
, 4, ... are 16, 0, 164, 1488, 12756, 62176, 379376, 2426224,
... (OEIS A123935; Kraitchik 1942, p. 263).
Like the
case, this sequence is known to be given by a linear recurrence
equation with constant coefficients, although
it appears this recurrence has not yet been explicitly computed.
The knight graph is Hamilton-laceable iff
,
, and at least one of
,
is even (Dupuis and Wagon 2015).