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Circular Segment


CircularSegment

A circular segment is a portion of a disk bounded by a chord and a circular arc. The illustration above shows a minor circular segment with central angle 0<theta<pi radians. The entire wedge-shaped area is known as a circular sector.

Circular segments are implemented in the Wolfram Language as DiskSegment[{x, y}, r, {q1, q2}]. Elliptical segments are similarly implemented as DiskSegment[{x, y}, {r1, r2}, {q1, q2}].

For this minor segment, let R>0 be the radius of the circle, a the chord length, s the arc length, h the height of the arced portion, and r the height of the triangular portion. Then the radius is

 R=h+r,
(1)

the arc length is

 s=Rtheta,
(2)

the height r is

r=Rcos(1/2theta)
(3)
=1/2acot(1/2theta)
(4)
=1/2sqrt(4R^2-a^2),
(5)

and the length of the chord is

a=2Rsin(1/2theta)
(6)
=2rtan(1/2theta)
(7)
=2sqrt(R^2-r^2)
(8)
=2sqrt(h(2R-h)).
(9)

From elementary trigonometry, the angle theta obeys the relationships

theta=s/R
(10)
=2cos^(-1)(r/R)
(11)
=2tan^(-1)(a/(2r))
(12)
=2sin^(-1)(a/(2R)).
(13)

The area A of the (shaded) segment is then simply given by the area of the circular sector (the entire wedge-shaped portion) minus the area of the bottom triangular portion,

 A=A_(sector)-A_(isosceles triangle).
(14)

Plugging in gives

A=1/2R^2(theta-sintheta)
(15)
=1/2(Rs-ar)
(16)
=R^2cos^(-1)(r/R)-rsqrt(R^2-r^2)
(17)
=R^2cos^(-1)((R-h)/R)-(R-h)sqrt(2Rh-h^2),
(18)

where the area formula for an isosceles triangle has been used (Beyer 1987). These formulas find application in the common case of determining the volume of fluid in a cylindrical segment (i.e., horizontal cylindrical tank) based on the height of the fluid in the tank.

With the circle centered at the origin and the chord at y=r, the area can also be found directly by integration as

 A=int_(-Rsin(theta/2))^(Rsin(theta/2))int_(Rcos(theta/2))^(sqrt(R^2-x^2))dydx.
(19)

The integral of y over this area is

M=int_(-Rsin(theta/2))^(Rsin(theta/2))int_(Rcos(theta/2))^(sqrt(R^2-x^2))ydydx
(20)
=2/3R^3sin^3(1/2theta),
(21)

so the y-coordinate of the geometric centroid of the circular segment is

 y^_=M/A=(4Rsin^3(1/2theta))/(3(theta-sintheta)).
(22)

This gives y^_->4R/(3pi) as theta->pi, the semicircle value, and y^_->R as theta->0, when the segment shrinks to the top of the circle.

CircularSegmentQuarter

Finding the value of h such that the circular segment (left figure) has area equal to 1/4 of the circle (right figure) is sometimes known as the quarter-tank problem.

Approximate formulas for the arc length and area are (Harris and Stocker 1998)

 s approx sqrt(a^2+(16)/3h^2),
(23)

accurate to within 0.3% relative error for 0 degrees<theta<=90 degrees, and

 A approx 2/3ah+(h^3)/(2a),
(24)

accurate to within 0.15% relative error for 0 degrees<theta<=150 degrees and 0.8% for 150 degrees<=theta<=180 degrees.


See also

Chord, Circle-Circle Intersection, Circular Sector, Cylindrical Segment, Horizontal Cylindrical Segment, Lens, Parabolic Segment, Quarter-Tank Problem, Reuleaux Triangle, Sagitta, Spherical Segment

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References

Beyer, W. H. (Ed.). CRC Standard Mathematical Tables, 28th ed. Boca Raton, FL: CRC Press, p. 125, 1987.Fukagawa, H. and Pedoe, D. "Segments of a Circle." §1.6 in Japanese Temple Geometry Problems. Winnipeg, Manitoba, Canada: Charles Babbage Research Foundation, pp. 14-15 and 88-92, 1989.Harris, J. W. and Stocker, H. "Segment of a Circle." §3.8.6 in Handbook of Mathematics and Computational Science. New York: Springer-Verlag, pp. 92-93, 1998.Kern, W. F. and Bland, J. R. Solid Mensuration with Proofs, 2nd ed. New York: Wiley, p. 4, 1948.Sloane, N. J. A. Sequence A133742 in "The On-Line Encyclopedia of Integer Sequences."

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Circular Segment

Cite this as:

Weisstein, Eric W. "Circular Segment." From MathWorld--A Wolfram Resource. https://mathworld.wolfram.com/CircularSegment.html

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