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Quarter-Tank Problem


CylindricalSegment

The quarter-tank problem asks for the height above the bottom of a horizontal cylinder (such as a cylindrical gas tank) to which it must be filled for it to be one quarter full. It is solved by plugging A=piR^2/4 (one quarter of the area of a full circle) into the equation for the area of a circular segment of radius R>0,

 A=R^2cos^(-1)((R-h)/R)-(R-h)sqrt(2Rh-h^2),
(1)

where 0<=h<=2R.

CircularSegmentQuarter

This gives equality between the two shaded areas in the above figure, resulting in

 1/4pi=cos^(-1)(1-x)-(1-x)sqrt(2x-x^2),
(2)

where x=h/R and R is the radius of the circle or cylinder. The unique solution with 0<x<1 is approximately x=0.596027... (OEIS A133742), corresponding to h approx 0.596027R.

The solution can also be expressed in terms of the Dottie number d, defined by d=cosd. The central angle theta of the quarter-filled circular segment satisfies

 theta-sintheta=1/2pi,
(3)

so theta=pi/2+d. The corresponding height is therefore given by

h/R=1-cos(1/4pi+1/2d)
(4)
=2sin^2(1/8pi+1/4d)
(5)

(M. J. Rodman, pers. comm., July 20, 2023).

The quarter-tank problem should not be confused with the German tank problem, which concerns statistical estimation from serial numbers.


See also

Circular Segment, Cylinder, Cylindrical Segment, Horizontal Cylindrical Segment

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References

Sloane, N. J. A. Sequence A133742 in "The On-Line Encyclopedia of Integer Sequences."

Referenced on Wolfram|Alpha

Quarter-Tank Problem

Cite this as:

Weisstein, Eric W. "Quarter-Tank Problem." From MathWorld--A Wolfram Resource. https://mathworld.wolfram.com/Quarter-TankProblem.html

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