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Covariant Tensor


A covariant tensor of tensor rank s on a vector space V is a scalar-valued multilinear map of s vectors. Its components have s lower indices, and it is a tensor of type (0,s). In finite dimensions it is an element of the tensor product (V^*)^( tensor s), where V^* is the dual vector space. On a manifold, V is the tangent space at the point under consideration. Rank 0 gives a scalar.

The rank-1 case is a covector, which takes a vector as input and returns a scalar linearly. For example, the differential of a smooth scalar-valued function f is the one-form

 df=(partialf)/(partialx^i)dx^i.
(1)

Applied to a tangent vector v, it gives the directional derivative

 df(v)=(partialf)/(partialx^i)v^i,
(2)

where repeated upper and lower indices are summed using Einstein summation.

Under a smooth invertible change of coordinates from x^i to x^('i), the chain rule gives

 (partialf^')/(partialx^('i))=(partialx^j)/(partialx^('i))(partialf)/(partialx^j),
(3)

where f^'(x^')=f(x). Any covector omega=omega_idx^i transforms by the same rule,

 omega_i^'=(partialx^j)/(partialx^('i))omega_j.
(4)

Writing K^j_i=partialx^j/partialx^('i) for the inverse Jacobian matrix, this becomes

 omega_i^'=K^j_iomega_j.
(5)

The transformation ensures that the value of a covector on a vector does not depend on coordinates,

 omega_i^'v^('i)=omega_jv^j.
(6)

For example, under x^'=2x in one dimension, omega^'=omega/2 and v^'=2v, so their product is unchanged. The vector is a rank-1 contravariant tensor.

For a covariant tensor of tensor rank s>=1, each lower index contributes an inverse Jacobian matrix factor,

 T_(i_1...i_s)^'=(partialx^(j_1))/(partialx^('i_1))...(partialx^(j_s))/(partialx^('i_s))T_(j_1...j_s).
(7)

A metric tensor g_(ij) is an example of a rank-2 covariant tensor. It acts on two vectors to give the scalar g_(ij)u^iv^j.

A nondegenerate metric tensor identifies vectors with covectors by index lowering,

 omega_i=g_(ij)v^j.
(8)

Conversely, the gradient vector associated with df is obtained by index raising,

 (del f)^i=g^(ij)(partialf)/(partialx^j),
(9)

where (g^(ij)) is the matrix inverse of (g_(ij)). Thus df requires no metric tensor, but its identification with a gradient vector does.

In an orthonormal basis of Euclidean space of any dimension, the metric tensor is the Kronecker delta, g_(ij)=delta_(ij). Corresponding upper- and lower-index components then agree numerically, as in the theory of Cartesian tensors. On a flat manifold with a Riemannian metric, such coordinates can be chosen locally. The equality of components need not hold in general coordinates.

In Minkowski space, index lowering instead introduces the signs of the Minkowski metric. For the convention g_(munu)=diag(-1,1,1,1) in an inertial coordinate system,

 v_0=-v^0,
(10)

while the spatial components are unchanged. With the opposite sign convention, the spatial components change sign instead. Both kinds of indices occur in a mixed tensor.


See also

Cartesian Tensor, Contravariant Tensor, Covector, Four-Vector, Gradient, Index Lowering, Metric Tensor, Mixed Tensor, One-Form, Tensor

Portions of this entry contributed by Manuel F. González Lázaro

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References

Arfken, G. "Noncartesian Tensors, Covariant Differentiation." §3.8 in Mathematical Methods for Physicists, 3rd ed. Orlando, FL: Academic Press, pp. 158-164, 1985.Lichnerowicz, A. Elements of Tensor Calculus. New York: Wiley, 1962.Morse, P. M. and Feshbach, H. Methods of Theoretical Physics, Part I. New York: McGraw-Hill, pp. 44-46, 1953.Weinberg, S. Gravitation and Cosmology: Principles and Applications of the General Theory of Relativity. New York: Wiley, 1972.

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Covariant Tensor

Cite this as:

Weisstein, Eric W., with contributions by Manuel F. González Lázaro. "Covariant Tensor." From MathWorld--A Wolfram Resource. https://mathworld.wolfram.com/CovariantTensor.html

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