Graham's biggest little hexagon is the largest possible (not necessarily regular) convex hexagon with polygon
diameter 1 (i.e., for which no two of the vertices
are more than unit distance apart). It is therefore
the biggest little polygon for the case
. The solution is given by the above figure (which
is shown with incorrect proportions in Conway and Guy 1996, p. 207), in which
the red lines are all diagonals
of unit length.
To find the hexagon, set up coordinates as illustrated
above, then the polygon area formula gives
(1)
Plugging in together with
(2)
(3)
and eliminating and then gives the formula for as
(4)
This function is plotted above. The parameter interval is , with and .
The unique maximum occurs at a stationary
point in (Graham 1975, pp. 168-169). The same algebraic
optimization can be formulated using Lagrange
multipliers for the unit-distance constraints and
a Gröbner basis to eliminate the coordinates
and multipliers (Trott 2006).
Maximizing gives the area of the hexagon
as the second-largest real root of
(5)
approximately given by (OEIS A111969).
Note that the sign of the is positive, not negative as erroneously given in Conway
and Guy (1996). Also compare this with the area of the regular hexagon of polygon
diameter 1 (and therefore having circumradius
1/2), which is given by
(6)
so the optimal solution is 3.9% larger.
The values of and corresponding to the maximal solution are given by
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