Bishops Problem
Find the maximum number of bishops
that can be
placed on an
chessboard
such that no two attack each other. The answer is
(Dudeney 1970,
Madachy 1979), giving the sequence 2, 4, 6, 8, ... (the even
numbers) for
, 3, .... One maximal solution for
is illustrated above. The numbers of distinct
maximal arrangements for
, 2, ... bishops
are 1, 4, 26, 260, 3368, ... (OEIS A002465).
The numbers of rotationally and reflectively distinct solutions on an
board for
is
![]() |
(1)
|
for
(Dudeney 1970, p. 96; Madachy
1979, p. 45; Pickover 1995). An equivalent formula also valid for
is
|
(2)
|
where
is the floor
function, giving the sequence for
, 2, ... as 1,
1, 2, 3, 6, 10, 20, 36, ... (OEIS A005418).
The minimum number of bishops needed to occupy or attack all squares on an
chessboard
is
, arranged as illustrated above.
![B(n)={2^((n-4)/2)[2^((n-2)/2)+1] for n even; 2^((n-3)/2)[2^((n-3)/2)+1] for n odd](/images/equations/BishopsProblem/NumberedEquation1.gif)
ANF (~P || Q) && (P || ~Q)