A Galois extension field of
is a normal extension
that is also a separable extension. For an
algebraic extension
, the following definitions are equivalent.
1.
is the splitting field for a collection of separable polynomials. When
is a finite extension,
then only one separable polynomial is necessary.
2. The common fixed field of all field automorphisms of that fix
is exactly
.
3. Every irreducible polynomial over which has a root
in
factors into linear factors in
. Also,
must be a separable extension.
4. Every field automorphism of the algebraic
closure
that fixes
satisfies
.
Also,
must be a separable extension.
A Galois extension has all of the above properties. For example, consider , the rational numbers
adjoined by the imaginary unit
, over
, which is a Galois extension. Note that
contains all of the roots
of
,
and is generated by them, so it is the splitting field
of
.
Of course, there are two distinct roots in
so it is separable. The only nontrivial
automorphism fixing
is given by complex conjugation
|
(1)
|
whose fixed field is . The only monic irreducible
polynomials with rational coefficients
with roots of the form
with
are
(
) and
(
). Both split into linear factors over
. Finally, the algebraic closure
is the set
of algebraic numbers in
. Every field automorphism
of the algebraic numbers fixing
sends
to
or
and therefore preserves
. In general, it is not so simple to verify all of these
properties, which makes their equivalence useful.
There are a couple of ways for an extension not to be a Galois extension. One is for it to not be a normal extension. For instance,
is not normal, and hence not Galois. It is missing the complex roots
of
.
Its only nontrivial automorphism is defined by
, which not only
fixes
but also the subfield
.
Another possibility for a non-Galois extension is for it to be not separable. The field characteristic of such a field
must be positive since all irreducible
polynomials are separable in characteristic zero. Moreover, all finite fields
are perfect, i.e., all algebraic
extensions are separable extensions. Consider
the field of rational
functions with coefficients in , infinite in size and
characteristic 2 (
).
|
(2)
|
and the extension
|
(3)
|
For instance,
and
.
Then
is the splitting field of
, as
in characteristic
2, and so it is a normal extension. However,
is not separable because
has repeated roots in
its splitting field,
.