Freeth's nephroid is a strophoid of a circle with the pole at the center of the circle
and the fixed point
on the circumference of
the circle. In the construction illustrated above,
is a moving point
on the circle, and
and
lie on the line
in opposite directions from
. The point
is obtained by moving away from
, and
by moving toward
, in each case through a distance
. Thus
, as indicated by the matching marks. As
moves around the circle, the two
points together trace Freeth's nephroid. Freeth (1878,
pp. 130 and 228) described this and various other strophoids
(MacTutor Archive).
The perpendicular bisector of cuts the outer boundary of Freeth's nephroid at the upper
point
illustrated above. The angle
is
, so this curve can be used to
construct a regular heptagon.
Freeth's nephroid has polar equation
|
(1)
|
for .
The area enclosed by the outer boundary of the curve is
|
(2)
|
and the total arc length over is
|
(3)
| |||
|
(4)
|
(OEIS A138498), where ,
is a complete
elliptic integral of the first kind,
is a complete
elliptic integral of the second kind, and
is a complete
elliptic integral of the third kind.
For ,
the curvature and the change in tangential
angle from its initial value are given by
|
(5)
| |||
|
(6)
|
where
is the floor function. Here
, so the absolute tangential
angle is
.
At odd multiples of
,
the value of
is defined by the limit of the expression above.