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Banach Matchbox Problem


The Banach matchbox problem asks for the probability mass function of the number of matches left in one of two boxes when the other is first found empty. Each box initially contains N matches, where N is a positive integer. The box choices form an independent sequence, with probability 1/2 for either box at each step. If it is nonempty, a match is removed. The experiment stops when an empty box is chosen, rather than when its last match is removed (Feller 1957, p. 157).

If the random variable K counts the matches remaining in the other box, then

 P(K=k)=((2N-k; N))/(2^(2N-k)),

where k=0, ..., N. For a specified box to be found empty with k matches in the other, its N successful selections and the other box's N-k selections must precede the final failed selection. Counting these orders and allowing either box to be found empty gives the formula. This is related to the negative binomial distribution.

The match-count calculations in Problem 193 of the Scottish Book Problems are tentatively interpreted as this problem in Beyer's commentary (Mauldin 2015, pp. 281-282).


See also

Negative Binomial Distribution

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References

Feller, W. An Introduction to Probability Theory and Its Applications, Vol. 1, 2nd ed. New York: Wiley, 1957.Mauldin, R. D. (Ed.). The Scottish Book: Mathematics from the Scottish Café, with Selected Problems from the New Scottish Book, 2nd ed. Cham, Switzerland: Birkhäuser, 2015. https://doi.org/10.1007/978-3-319-22897-6.

Cite this as:

Weisstein, Eric W. "Banach Matchbox Problem." From MathWorld--A Wolfram Resource. https://mathworld.wolfram.com/BanachMatchboxProblem.html

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