The intangents circle is the circumcircle of the intangents triangle.
It has circle function
 |
(1)
|
where
 |
(2)
|
which is not a Kimberling center.
Its center has center function
 |
(3)
|
and it has radius
 |
(4)
|
where 
is the inradius of the reference
triangle.
No Kimberling centers lie on the intangents circle.
Let 
be the center of the intangents circle and 
the center of the extangents
circle. Both centers lie on the line (26, 55), and both centers are on lines
parallel to the Euler line through simple points (
and 
, respectively). Amazingly, the midpoint of 
is the circumcenter of the tangential triangle 
, which lies on the Euler line
(P. Moses, pers. comm., Jan. 15, 2005).
