The intangents circle is the circumcircle of the intangents triangle.
It has circle function
(1)

where
(2)

which is not a Kimberling center.
Its center has center function
(3)

and it has radius
(4)

where is the inradius of the reference triangle.
No Kimberling centers lie on the intangents circle.
Let be the center of the intangents circle and the center of the extangents circle. Both centers lie on the line (26, 55), and both centers are on lines parallel to the Euler line through simple points ( and , respectively). Amazingly, the midpoint of is the circumcenter of the tangential triangle , which lies on the Euler line (P. Moses, pers. comm., Jan. 15, 2005).