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Inner Inscribed Squares Triangle


TriangleSquareInscribing1

Externally erect a square on the side BC. Now join the new vertices S_(AB) and S_AC of this square with the vertex A, marking the points of intersection Q_(A,BC) and Q_(A,CB). Next, draw the perpendiculars to BC through Q_(A,BC) and Q_(A,CB). These lines intersect AB and AC respectively in Q_(AB) and Q_(AC). This results in the A^+-inscribed square Q_(A,BC)Q_(A,CB)Q_(AB)Q_(AC).

The triangle has area

 Delta_I=(a^2b^2c^2cosAcosBcosC)/(2(a^2+2Delta)(b^2+2Delta)(c^2+2Delta))Delta,

where Delta is the area of the reference triangle.


See also

Triangle Square Inscribing, Outer Inscribed Squares Triangle

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Cite this as:

Weisstein, Eric W. "Inner Inscribed Squares Triangle." From MathWorld--A Wolfram Web Resource. https://mathworld.wolfram.com/InnerInscribedSquaresTriangle.html

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