A Galois group of an extension field is the group
of automorphisms
of
such that
for every
. Thus
is fixed. The Galois group of
is denoted
or
.
Let be a rational
polynomial of polynomial degree
with distinct roots, and let
be the splitting
field of
over
, i.e., the smallest subfield
of
containing all the roots
of
. Then each element of the Galois group
permutes the roots of
in a unique way. Thus
can be identified with a subgroup
of the symmetric group
, the group of permutations
of the roots of
. If
is irreducible,
then
is a transitive subgroup
of
, i.e., given two roots
and
of
, there exists an element
of
such that
.
The roots of are solvable by radicals iff
is a solvable
group. Since all subgroups of
with
are solvable, the
roots of all polynomials
of polynomial degree up to 4 are solvable by
radicals. However, polynomials
of polynomial degree 5 or greater are generally
not solvable by radicals since
(and the alternating group
) are not solvable
for
.
For an irreducible polynomial over of polynomial
degree 3, the Galois group is the alternating
group
if its polynomial discriminant is the
square of a rational number,
and the symmetric group
otherwise (Milne 2022, p. 49).
For a finite Galois extension field
generated by a primitive element
, each automorphism
is determined by its image of
. These images are precisely
the roots of the extension
field minimal polynomial of
over
. Thus a primitive-element representation
realizes the group through the conjugates
of one generator.
The inverse Galois problem asks whether every finite group is isomorphic to a Galois
group
for some finite Galois
extension field
. The problem remains open in
general. Huang et al. (2026) proved that the Mathieu
group M23 occurs in this way, completing the realization of
all 26 sporadic groups over
.
The Galois group of
consists of the identity element and complex
conjugation. These functions both take a given real to the same real number.