Given a unit disk, find the smallest radius required for
equal disks to completely cover the unit
disk. The first few such values are
|
(1)
| |||
|
(2)
| |||
|
(3)
| |||
|
(4)
| |||
|
(5)
| |||
|
(6)
| |||
|
(7)
| |||
|
(8)
| |||
|
(9)
| |||
|
(10)
|
Here, values for ,
8, 9, 10 are approximate values obtained using computer experimentation by Zahn (1962).
For a symmetrical arrangement with (known as the five disks
problem),
,
where
is the golden ratio. However, rather surprisingly,
the radius can be slightly reduced in the general disk covering problem where symmetry
is not required; this configuration is illustrated above (Friedman). Neville (1915)
showed that the value
is equal to
, where
and
are solutions to
|
(11)
| |
|
(12)
| |
|
(13)
| |
|
(14)
|
These solutions can be found exactly as
|
(15)
| |||
|
(16)
|
where
|
(17)
| |
|
(18)
|
are the smallest positive roots of the given polynomials, with denoting the
th root of the polynomial
in the ordering of the Wolfram
Language. This gives
(OEIS A133077)
exactly as
|
(19)
|
where the root is the smallest positive one of the above polynomial.
is also given by
,
where
is the largest real root of
|
(20)
|
maximized over all , subject to the constraints
|
(21)
|
|
(22)
|
and with
|
(23)
| |||
|
(24)
| |||
|
(25)
| |||
|
(26)
| |||
|
(27)
| |||
|
(28)
| |||
|
(29)
|
(Bezdek 1983, 1984).
Letting
be the smallest number of disks of radius
needed to cover a disk
, the limit of the ratio of the area
of
to the area of the disks is given by
|
(30)
|
(OEIS A086089; Kershner 1939, Verblunsky 1949).