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Congruent Incircles


Incircles

Congruent incircles are incircles of equal radius. One construction draws a cevian in a triangle that divides it into two triangles with equal inradii. The positions and sizes of these two incircles can then be determined by simultaneously solving the eight equations

x_1=(tan(1/2theta_(12)))/(tan(1/2theta_(11))+tan(1/2theta_(12)))d_1
(1)
x_2=(tan(1/2theta_(22)))/(tan(1/2theta_(21))+tan(1/2theta_(22)))d_2
(2)
a=(tan(1/2theta_(11))tan(1/2theta_(12)))/(tan(1/2theta_(11))+tan(1/2theta_(12)))d_1
(3)
a=(tan(1/2theta_(21))tan(1/2theta_(22)))/(tan(1/2theta_(21))+tan(1/2theta_(22)))d_2
(4)
h=(tantheta_(11)tantheta_(12))/(tantheta_(11)+tantheta_(12))d_1
(5)
h=(tantheta_(21)tantheta_(22))/(tantheta_(21)+tantheta_(22))d_2
(6)
d=d_1+d_2
(7)
pi=theta_(12)+theta_(21)
(8)

for the eight variables d_1, d_2, theta_(12), theta_(21), a, x_1, x_2, and h, with theta_(11), theta_(22), and d given. Generalizing to n congruent circles gives the 4n equations

x_i=(tan(1/2theta_(i2)))/(tan(1/2theta_(i1))+tan(1/2theta_(i2)))d_i
(9)
a=(tan(1/2theta_(i1))tan(1/2theta_(i2)))/(tan(1/2theta_(i1))+tan(1/2theta_(i2)))d_i
(10)
h=(tantheta_(i1)tantheta_(i2))/(tantheta_(i1)+tantheta_(i2))d_i
(11)

for i=1, ..., n,

 theta_(i2)+theta_(i+1,1)=pi
(12)

for i=1, ..., n-1, and

 d=sum_(i=1)^nd_i
(13)

to be solved for the unknowns d_i and x_i (n of them), theta_(i1) and theta_(i2) (n-2 of each for i=2, ..., n-1), and theta_(12), theta_(n1), a, and h, a total of n+n+2(n-2)+4=4n unknowns.

For a single cevian CD dividing DeltaABC into two triangles with equal inradii, write a=BC, b=CA, c=AB, s=(a+b+c)/2, and let Delta be the triangle area. The cevian length L=CD, common inradius rho, and division of AB are given explicitly by

CD=sqrt(s(s-c))
(14)
rho=Delta/(s+L)
(15)
AD=(c(b+L))/(a+b+2L)
(16)
DB=(c(a+L))/(a+b+2L).
(17)

The length and radius formulas are given by Jackson and Takhaev (2015, p. 5). The equal-inradius condition gives AD/DB=(b+L)/(a+L), and Stewart's theorem then gives L^2=s(s-c). Yiu (2003) gives a systematic treatment of these cevians.

Given an arbitrary triangle, let n-1 cevians be drawn from one of its vertices so all of the n triangles so determined have equal incircles. The equal incircles theorem says that the incircles determined by spanning 2, 3, ..., n-1 adjacent triangles are also equal (Wells 1991, p. 67).


See also

Congruent Incircles Point, Equal Incircles Theorem, Incircle

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References

Bogomolny, A. "Equal Incircles Theorem." https://cut-the-knot.org/Curriculum/Geometry/AdjacentIncircles.shtml.Jackson, F. M. and Takhaev, S. "Heronian Triangles of Class K: Congruent Incircles Cevian Perspective." Forum Geom. 15, 5-12, 2015.Wells, D. The Penguin Dictionary of Curious and Interesting Geometry. London, England: Penguin, 1991.Yiu, P. "The Congruent-Incircle Cevians of a Triangle." Missouri J. Math. Sci. 15, 21-32, 2003. https://doi.org/10.35834/2003/1501021.

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Congruent Incircles

Cite this as:

Weisstein, Eric W. "Congruent Incircles." From MathWorld--A Wolfram Resource. https://mathworld.wolfram.com/CongruentIncircles.html

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