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Let a cone of opening parameter and vertex at intersect a sphere of radius centered at , with the cone oriented such that its axis does not pass through the center of the sphere. Then the equations of the curve of intersection are
(1)
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(2)
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(3)
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(4)
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Therefore, and are connected by a complicated quartic equation, and , , and by a quadratic equation.
If the cone-sphere intersection is on-axis so that a cone of opening parameter and vertex at is oriented with its axis along a radial of the sphere of radius centered at , then the equations of the curve of intersection are
(5)
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(6)
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(7)
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(8)
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(9)
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Using the quadratic equation gives
(10)
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(11)
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So the curve of intersection is planar. Plugging (11) into (◇) shows that the curve is actually a circle, with radius given by
(12)
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