Thomsen's Figure

DOWNLOAD Mathematica Notebook ThomsensFigure

Take any triangle with polygon vertices A, B, and C. Pick a point A_1 on the side opposite A, and draw a line parallel to BC. Upon reaching the side AC at B_1, draw the line parallel to AB. Continue (left figure). Then the line closes for any triangle. If A_1 is the midpoint of BC, then A_2=A_1 (right figure).

ThomsensFigureCoordinates

Let k be the ratio in which the sides of the reference triangle are divided i.e., k=AB_1/AC=BA_2/BC=CB_2/CA, and define k^'=1-k. Then the coordinates of the vertices of the figure are shown above.

The six vertexes of Thomsen's figure lie on an ellipse having the triangle centroid as its center. The area of this ellipse is

 A=(4pi)/(3sqrt(3))(3k^2-3k+1)Delta,

where Delta is the area of the reference triangle. When k=0 (or k=1), the ellipse becomes the Steiner circumellipse, and when k=1/2, it becomes the Steiner inellipse (M. Tarquini, pers. comm., Sep. 2, 2005).

Thomsen's figure is similar to a Tucker hexagon. While Thomsen's hexagon closes after six parallels, a Tucker hexagon closes after alternately three parallels and three antiparallels.

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