If
is continuous in a region
and satisfies
for all closed contours in
, then
is analytic in
.
Morera's theorem does not require simple connectedness, which can be seen from the following proof. Let
be a region, with
continuous on
,
and let its integrals around closed loops be zero. Pick any point
, and pick a neighborhood
of
.
Construct an integral of
,
Then one can show that ,
and hence
is analytic and has derivatives of all orders,
as does
,
so
is analytic at
.
This is true for arbitrary
, so
is analytic in
.
It is, in fact, sufficient to require that the integrals of around triangles be zero, but this is a technical point. In
this case, the proof is identical except
must be constructed by integrating along the line segment
instead of along an arbitrary path.