Law of Sines

EXPLORE THIS TOPIC IN the MathWorld Classroom LawofSines

Let a, b, and c be the lengths of the legs of a triangle opposite angles A, B, and C. Then the law of sines states that

 a/(sinA)=b/(sinB)=c/(sinC)=2R,
(1)

where R is the radius of the circumcircle. Other related results include the identities

 a(sinB-sinC)+b(sinC-sinA)+c(sinA-sinB)=0
(2)
 a=bcosC+ccosB,
(3)

the law of cosines

 cosA=(c^2+b^2-a^2)/(2bc),
(4)

and the law of tangents

 (a+b)/(a-b)=(tan[1/2(A+B)])/(tan[1/2(A-B)]).
(5)

The law of sines for oblique spherical triangles states that

 (sina)/(sinA)=(sinb)/(sinB)=(sinc)/(sinC).
(6)

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