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Bernoulli Inequality


The Bernoulli inequality states

 (1+x)^n>1+nx,
(1)

where x>-1!=0 is a real number and n>1 an integer.

This inequality can be proven by taking a Maclaurin series of (1+x)^n,

 (1+x)^n=1+nx+1/2n(n-1)x^2+1/6n(n-1)(n-2)x^3+....
(2)

Since the series terminates after a finite number of terms for integral n, the Bernoulli inequality for x>0 is obtained by truncating after the first-order term.

When -1<x<0, slightly more finesse is needed. In this case, let y=|x|=-x>0 so that 0<y<1, and take

 (1-y)^n=1-ny+1/2n(n-1)y^2-1/6n(n-1)(n-2)y^3+....
(3)

Since each power of y multiplies by a number <1 and since the absolute value of the coefficient of each subsequent term is smaller than the last, it follows that the sum of the third order and subsequent terms is a positive number. Therefore,

 (1-y)^n>1-ny,
(4)

or

 (1+x)^n>1+nx,    for -1<x<0,
(5)

completing the proof of the inequality over all ranges of parameters.

For x>-1!=0, the following generalizations of Bernoulli inequality are valid for real exponents:

 (1+x)^a>1+ax     if a>1 or a<0,
(6)

and

 (1+x)^a<1+ax     if 0<a<1
(7)

(Mitrinović 1970).


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References

Mitrinović, D. S. Analytic Inequalities. New York: Springer-Verlag, 1970.

Referenced on Wolfram|Alpha

Bernoulli Inequality

Cite this as:

Weisstein, Eric W. "Bernoulli Inequality." From MathWorld--A Wolfram Web Resource. https://mathworld.wolfram.com/BernoulliInequality.html

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