Tetrahedral Number

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A figurate number Te_n of the form

Te_n=sum_(k=1)^(n)T_k
(1)
=1/6n(n+1)(n+2)
(2)
=(n+2; 3),
(3)

where T_k is the kth triangular number and (n; m) is a binomial coefficient. These numbers correspond to placing discrete points in the configuration of a tetrahedron (triangular base pyramid). Tetrahedral numbers are pyramidal numbers with r=3, and are the sum of consecutive triangular numbers. The first few are 1, 4, 10, 20, 35, 56, 84, 120, ... (OEIS A000292). The generating function for the tetrahedral numbers is

 x/((x-1)^4)=x+4x^2+10x^3+20x^4+....
(4)

Tetrahedral numbers are even, except for every fourth tetrahedral number, which is odd (Conway and Guy 1996).

The only numbers which are simultaneously square and tetrahedral are Te_1=1, Te_2=4, and Te_(48)=19600 (giving S_1=1, S_2=4, and S_(140)=19600), as proved by Meyl (1878; cited in Dickson 2005, p. 25).

Numbers which are simultaneously triangular and tetrahedral satisfy the binomial coefficient equation

 T_n=(n+1; 2)=(m+2; 3)=Te_m,
(5)

the only solutions of which are

Te_1=T_1=1
(6)
Te_3=T_4=10
(7)
Te_8=T_(15)=120
(8)
Te_(20)=T_(55)=1540
(9)
Te_(34)=T_(119)=7140
(10)

(OEIS A027568; Avanesov 1966/1967; Mordell 1969, p. 258; Guy 1994, p. 147).

Beukers (1988) has studied the problem of finding numbers which are simultaneously tetrahedral and pyramidal via integer points on an elliptic curve, and finds that the only solution is the trivial Te_1=P_1=1.

The minimum number of tetrahedral numbers needed to sum to n=1, 2, ... are given by 1, 2, 3, 1, 2, 3, 4, 2, 3, 1, ... (OEIS A104246). Pollock's conjecture states that every number is the sum of at most five tetrahedral numbers. The numbers that are not the sum of <=4 tetrahedral numbers are given by the sequence 17, 27, 33, 52, 73, ..., (OEIS A000797) containing 241 terms, with 343867 being almost certainly the last such number.

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